m^2=351

Solution for m^2=351 equation:

m^2=351

We move all terms to the left:

m^2-(351)=0

a = 1; b = 0; c = -351;
Δ = b2-4ac
Δ = 02-4·1·(-351)
Δ = 1404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1404}=\sqrt{36*39}=\sqrt{36}*\sqrt{39}=6\sqrt{39}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{39}}{2*1}=\frac{0-6\sqrt{39}}{2}
=-\frac{6\sqrt{39}}{2}
=-3\sqrt{39}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{39}}{2*1}=\frac{0+6\sqrt{39}}{2}
=\frac{6\sqrt{39}}{2}
=3\sqrt{39}
$